Answer:
5.51g
Explanation:
Using the following formula:
Q = m × c × ∆T
Where;
Q = amount of heat in Joules
m = mass/weight of Aluminum
c = specific heat of Aluminum (0.900 J/g°C)
∆T = change in temperature.
Based on the information given in this question, Q = 175.6 joules, ∆T = 35.4°C, c = 0.900 J/g°C.
Using, Q = m × c × ∆T
175.6 = m × 0.900 × 35.4
175.6 = 31.86m
m = 175.6/31.86
m = 5.51g
The weight of the aluminum sample is 5.51g.
