Assume that θ is an acute angle in a right triangle satisfying the given conditions. Evaluate the 5 remaining trigonometric functions. Sketch a triangle in the correct quadrant and label.

sec θ= 17/15
sin θ<0

Assume that θ is an acute angle in a right triangle satisfying the given conditions Evaluate the 5 remaining trigonometric functions Sketch a triangle in the co class=

Respuesta :

Answer: See step by step. Replace the x with theta

Step-by-step explanation: Since sin is less than zero, and secant is positive. This means the trig values are in Quadrant 4.

We know that secФ=17/15. We need to find sin,cos,tan,csc, and cot.

We can find tangent by using the identity

[tex]tan^{2} (x)+ 1=sec^{2} (x)[/tex] where x is theta.

[tex]tan^{2} (x)+1=\frac{289}{225}[/tex]

[tex]tan^{2} (x)+\frac{225}{225} =\frac{289}{225}[/tex]

[tex]tan^{2}(x)=\frac{64}{225}[/tex]

tan x=[tex]\frac{8}{15}[/tex], Tangent in the fourth  quadrant is negative  so  the answer is instead

[tex]tan x= -\frac{8}{15}[/tex]

We can find cotangent by taking the recipocial of tan so

[tex]cot=-\frac{15}{8}[/tex]

We can find cos by taking reciprocal of sec remeber that cosine is positive in 4th quadrant so the answer is

[tex]cos =\frac{15}{17}[/tex]

We can find sin by doing quoteint identies.

[tex]\frac{sin x}{cos x} =tan x[/tex]

[tex]\frac{ sin x}{15/17} =-\frac{8}{15}[/tex]

[tex]sin x= -\frac{8}{17}[/tex]

To find csc, take reciprocal of sine.

[tex]csc=\frac{-17}{8}[/tex]