Can anyone help me plz?
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Answer:
[tex] y = \frac{1}{4}x + 1 [/tex]
Step-by-step explanation:
Line is passing through the points (0, 1) & (4, 2)
Slope of line = (2 - 1)/(4 - 0) = 1/4
y-intercept (b) = 1
Equation of line in slope-intercept form is given as:
[tex]y = mx + b \\ \\ y = \frac{1}{4}x + 1 [/tex]
Answer:
[tex]y = \frac{1}{4}x + 1[/tex]
Step-by-step explanation:
Slope intercept form allows one to write an equation for a line from only the y-intercept and the slope, so we need to identify those two things.
The slope is simply [tex]\frac{y_2 - y_1}{x_2-x_1}[/tex]=>[tex]\frac{2-1}{4-0}[/tex]=> 1/4
The slope intercept is the y value when x = 0, and since we have the point (0,1), the y-intercept must be 1
The equation is: y = mx + b where m is the slope and b is the intercept so the final equation is:
[tex]y = \frac{1}{4}x + 1[/tex]