Answer:
The answer is "0.500".
Step-by-step explanation:
The chance that round will be won, [tex]P (win) =0.8[/tex]
The likelihood of losing round by complementary law
[tex]P(loss) = 1 -P(win)\\\\[/tex]
[tex]=1-0.8\\\\=0.2\\\\[/tex]
Let X be the number of rounds to the first loss played.
Here, [tex]X \sim Geometric (p=0.2)[/tex]
The PMF of X is the following:
[tex]P(X=x)=p(1-p)^x\\\\[/tex]
[tex]=(0.2)(1-0.2)^x\\\\=(0.2)(0.8)^x, \ \ \ \ \ x=1,2,.....[/tex]
The mean of X is the geometric random variable property, [tex]E(X) =\frac{1}{P}= \frac{1}{0.2}=5\\\\[/tex]
Markov's Inequality:
Suppose X is any random variable that has no negatives. So,
[tex]P(X \geq s)\leq \frac{E(X)}{s} for s >0\\\\[/tex]
Find the upper bound of [tex]P (X \geq 10)[/tex]
[tex]P(X \geq 10) \leq \frac{E(X)}{10}[/tex]
[tex]=\frac{5}{10}\\\\=\frac{1}{2}\\\\=0.5\\\\[/tex]
The highest probability is, therefore, that Markov's inequality will win at least ten rounds: 0.500