I need help with this question ( see image). Please show workings.
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Answer:
(a) ∠KHG = 120°
(b) (i) KG = 15.625 km
(b) (ii) bearing of G from K = 240°
Step-by-step explanation:
(a) 360° - 290° = 70°
∠KHG = 70° + 50° = 120°
(b) (i) ∠KGH = 26°
∠GKH = 34°
KG = 7.875 + 7.75 = 15.625 km
(b)(ii) Bearing from G from K = 110° + 130° = 240°