Answer:
9 units
Step-by-step explanation:
Given: Two points on a coordinate plane are [tex](-5,9),\,(4,9)[/tex]
To find: distance between points [tex](-5,9),\,(4,9)[/tex]
Solution:
According to the distance formula,
Distance between points [tex](a,b)[/tex] and [tex](c,d)[/tex] is equal to [tex]\sqrt{(c-a)^2+(d-b)^2}[/tex]
Take [tex](a,b)=(-5,9),\,(c,d)=(4,9)[/tex]
Therefore,
Distance between points [tex](-5,9),\,(4,9)[/tex] [tex]=\sqrt{(4+5)^2+(9-9)^2}[/tex]
[tex]=\sqrt{(9)^2}[/tex]
[tex]=9[/tex] units
