The approximate volume of first cone is 709[tex]mi^{3}[/tex] and the volume of second cone is 262 [tex]cm^{3}[/tex].
Volume is amount of substance a container can hold in its capacity. Volume of cone is basically 1/3 *π[tex]r^{2}h[/tex] in which r is radius and h is height of cone.
We have been given two cones. First is having radius of 7 mi and
height 14 mi and second is having radius of 5 cm and height of 10 cm. We are required to find out the volume of both the cones.
Volume of first cone=1/3 *π[tex]7^{2}* 14[/tex]
=(49*3.14*14)/3
=708.86
Approximately 709 [tex]mi^{3}[/tex]
Volume of second cone =1/3π[tex]5^{2} *10[/tex]
=(25*3.14*10)/3
=261.67
Approximately 262 [tex]cm^{3}[/tex].
Hence the approximate volume of first cone is 709[tex]mi^{3}[/tex] and the volume of second cone is 262 [tex]cm^{3}[/tex].
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