Answer:
48π in³
Step-by-step explanation:
[tex]V=\frac{1}{3} \pi r^2h[/tex]
Plug in the radius 6 in and the height 4 in
[tex]V=\frac{1}{3} \pi (6)^2(4)\\V=\frac{1}{3} \pi (36)(4)\\V=\frac{1}{3} \pi (144)\\V=48\pi[/tex]
Therefore, the volume of the cone is 48π in³.
I hope this helps!
