Respuesta :

Answer:

let's divide the figure into two parts.

area of square =side²

area of square=(8in)²

area of square = 64in²

area of triangle=1/2×base ×height

area of triangle =1/2×8×8

area of triangle =32in²

area of the figure=64in²+32in²

area of figure=96in²

Answer:

96 in. ^2

Step-by-step explanation:

Since it requires the use of triangle and square formules where the triangle is A=1/2bh and the square (being a quadrilateral) is A=bh, it's basically A=1/2bh + A=bh. We know that a square has all equal sides, so it's safe to assume that all sides are 8 inches, especially the side where it's connected to the triangle.

The side where it connects with the triangle can be considered the triangle's base since their lengths are similar.

So based on the information given, we can substitute:

  • A=1/2bh to A=1/2(8)(8)
  • A=bh to A=(8)(8)

Solve.

A=1/2(8)(8)

A=1/2(64)

A=64/2

A=32

A=(8)(8)

A=64

Add and you get 96 in. ^2

:p