Answer: The volume of sample at 400 K is [tex]285cm^3[/tex]
Explanation:
Charles' Law: This law states that volume is directly proportional to the temperature of the gas at constant pressure and number of moles.
[tex]V\propto T[/tex] (At constant pressure and number of moles)
[tex]{\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]
where,
[tex]V_1[/tex] = initial volume of gas = [tex]257cm^3[/tex]
[tex]V_2[/tex] = final volume of gas = ?
[tex]T_1[/tex] = initial temperature of gas = 360 K
[tex]T_2[/tex] = final temperature of gas = 400 K
Putting in the values we get:
[tex]{\frac{257}{360}=\frac{V_2}{400}[/tex]
[tex]V_2=285cm^3[/tex]
Thus volume of sample at 400 K is [tex]285cm^3[/tex]
