Respuesta :
Answer :
no. of days used to repair 1250m of road = 5
no. of days used to repair 1m of road = 5/1250
no. of days used to repair 8000m of road (8*1000m ) = 5/1250*8000= 32 days
5 days. 1250 meters
x days 8km=8000 meters
X=5•8000/1250
X=40000/1250
X=32 days
x days 8km=8000 meters
X=5•8000/1250
X=40000/1250
X=32 days