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Answer:
The sum of two numbers is 14 and their difference is 10
Step-by-step explanation:
"2 numbers (x and y)
x+y = 14
and x-y + 10
If you each equation by positive 2, one gets 2x+2y = 28 and 2x-2y = 20
The 'y-terms' cancel out or equal zero when adding, so 4x = 48, divide by 4 on each side and x or the first number equals 12.
Plug 12 back into the equation for 'x' and subtract 12 on both sides so that y=2
The difference of 12-2=10 and the addition of 12 and 2 equals 14"
hopes this helps
The first number, x, is 3.5. The other number, y, is 10.5.
X+y=-7
X-y=14.
Those are the two equations. If you use the elimination method, and add those two equations together, the resulting equation is 2x=7. That means the first variable is 3.5. So, 3.5-y=-7, so that means y is -10.5. If you plug that in with the other equation then it comes out as true.
X+y=-7
X-y=14.
Those are the two equations. If you use the elimination method, and add those two equations together, the resulting equation is 2x=7. That means the first variable is 3.5. So, 3.5-y=-7, so that means y is -10.5. If you plug that in with the other equation then it comes out as true.