there is a mistake in each fraction-
please describe what went wrong (all of em)
No huge explanation needed- just answers- PLEASE!!!!
Would give more pts if i had them

there is a mistake in each fraction please describe what went wrong all of em No huge explanation needed just answers PLEASE Would give more pts if i had them class=

Respuesta :

Answer:

1) They forgot to multiply 2 times (2x+5)

2) x-2 is not equal to -(x+2).

3) The correct expression is [tex]x-1-1+2x=1-3x[/tex]

4) The correct way is [tex]4(2x+3)=3(1-3x)[/tex]

Step-by-step explanation:

1) In this case they forgot to multiply 2 times (2x+5). Let's recall we need to multiply (2x+5) to all terms of the equation.

2) Here, x-2 is not equal to -(x+2). If we see -(x+2) = -x-2 using the distributive property.

3) After multiplying by (3x-2) we will have:

[tex]x-1-(1-2x)=1-3x[/tex]

Apply the distributive property again, we will have:

[tex]x-1-1+2x=1-3x[/tex]

So the correct term is 2x not -2x.

4) When we multiply by (1-3x)(2x+3) on each side of the equation, we will have something like this:

[tex]\frac{4(1-3x)(2x+3)}{(1-3x)}=\frac{3(1-3x)(2x+3)}{(2x+3)}[/tex]

If we see we can simplify the same terms on each side of the equation.

[tex]4(2x+3)=3(1-3x)[/tex]

This is the correct way to do this.

I hope it helps you!