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Alcohol is used as a source of fuel for some automobiles. The standard molar enthalpy of formation of ethanol C2H5OH(l) is -277.6 kJ/mol. For the balanced reaction equation of ethanol use:

C2H5OH(l) + 3O2 --> 2CO2 + 3H2O.

Ethanol is a liquid, but all the other chemicals in this reaction are gases. What is the enthalpy change of this reaction in kJ/mol?

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sebassandin

Answer:

[tex]\Delta _rH=-1,234.8kJ/mol[/tex]

Explanation:

Hello!

In this case, according to the given chemical reaction, it is possible to calculate the enthalpy change of the reaction via:

[tex]\Delta _rH=2\Delta _fH_{CO_2}+3\Delta _fH_{H_2O}-\Delta _fH_{C_2H_5OH}[/tex]

Since the enthalpy of formation of oxygen is 0. Thus, given the enthalpies of formation of gaseous carbon dioxide and water, we obtain:

[tex]\Delta _rH=2(-393.5kJ/mol)+3(-241.8kJ/mol)-(-277.6kJ/mol)\\\\\Delta _rH=-1,234.8kJ/mol[/tex]

Best regards!

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