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a 30 kg cart is travelling in a zero friction environment at a constant velocity of 5m/s. It's about to go up a very steep hill. How high will the cart be when the velocity changes to zero? PLEASE HELP

Respuesta :

Answer:

1.27551m

Explanation:

This is a simple energy convertion problem. Since there is no friction, and assuming no air drag and other external factors, mechanical energy should be conserved in this system.

Thus, we get:

[tex]KE_{initial} + PE_{initial} = KE_{final} + PE_{final}[/tex]

We also know that the gravitational potential energy is equal to mgh, while the KE can be calculated using [tex]\frac{1}{2}mv^2[/tex]

One thing to note here, is that the final KE will be 0, as there is no velocity at the end. Furthermore, we also can set the initial PE as 0 as we are looking at relative height, and at the start it is at h=0.

[tex]KE_{initial} = PE_{final}[/tex]

Plugging in:

[tex]\frac{1}{2}*30*5^2 = 30*9.8*h[/tex]

Solving for h, we get 1.27551m