Please help me solve these are quadratic equations: I
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Answer:
[tex]\boxed {\boxed {\sf a= 3, b=7, c=2}}[/tex]
[tex]\boxed {\boxed {\sf Y-intercept = c }}[/tex]
[tex]\boxed {\boxed {\sf Minimum}}[/tex]
Step-by-step explanation:
a. a, b, c
Quadratic equations in standard form are written as:
[tex]f(x)= ax^2+bx+c[/tex]
The exponents are listed from greatest to least. The quadratic is already in this form, so match up the variables and values in the equation.
[tex]f(x)= 3x^2+7x+2[/tex]
[tex]a=3 \\b=7 \\c=2[/tex]
b. Y-intercept
The y-intercept for a quadratic is c.
You can also substitute 0 in for x, because the y-intercept occurs when the quadratic crosses the y-axis (at x=0).
[tex]f(0)= 3(0)^2+7(0)+2[/tex]
[tex]f(0)=3(0)+7(0)+2\\f(0)= 0+0+2\\f(0)=2[/tex]
We know that c=2, so the y-intercept is c.
c. Maximum/minimum
The entire quadratic is positive, so the quadratic opens up and has a minimum.