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Calculate the equivalent molar concentration of sodium hydroxide if the titration of 20,00 ml of 0,05075 M solution of oxalic acid consumed 19,50 ml of this solution.

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Answer:

0.1041 M

Explanation:

The reaction that takes place is:

  • 2NaOH + H₂C₂O₄ → Na₂C₂O₄ + 2H₂O

First we calculate how many moles of oxalic acid reacted, using the given molarity and concentration:

  • 20.00 mL * 0.05075 M = 1.015 mmol H₂C₂O₄

Then we convert H₂C₂O₄ moles to NaOH moles, using the stoichiometric coefficients:

  • 1.015 mmol H₂C₂O₄ * [tex]\frac{2mmolNaOH}{1mmolH_2C_2O_4}[/tex] = 2.03 mmol NaOH

Finally we calculate the molarity of the NaOH solution:

  • 2.03 mmol NaOH / 19.50 mL = 0.1041 M

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