Answer:
The appropriate alternative is option C "[tex]5.09\times 10^{14} \ s[/tex]".
Explanation:
The given value is:
Energy of photon,
E = [tex]3.37\times 10^{-19} \ J[/tex]
As we know,
h = [tex]6.626\times 10^{-34} \ Js[/tex]
Now,
The frequency of the light will be:
⇒ [tex]E=hv[/tex]
On substituting the given values, we get
⇒ [tex]3.37\times 10^{-19}=6.626\times 10^{-34}\times v[/tex]
On solving, we get
⇒ [tex]v=5.09\times 10^{14} \ s[/tex]
If the energy of a photon of light is 3.37 x 10⁻¹⁹ J, then the frequency of the light is 5.09 x 10¹⁴ per sec.
Frequency of light will be calculated by using the below formula:
E = hυ, where
E = energy of photon = 3.37 x 10⁻¹⁹ J
h = plank's constant = 6.626 × 10⁻³⁴ Js
Putting these values on the above equation and calculate for the frequency as:
υ = 3.37 x 10⁻¹⁹ J / 6.626 × 10⁻³⁴ Js = 5.09 x 10¹⁴ per sec
Hence, option (C) is correct i.e. 5.09 x 10¹⁴ per sec.
To know more about frequency, visit the below link:
https://brainly.com/question/254161
