Answer:
Final velocity of ball B V2 = 8 m/s
Explanation:
Given:
Mass of Ball A M1 = 12 gram
Mass of Ball B M2 = 36 gram
Initial velocity of ball A U1 = 15 m/s
Initial velocity of ball B U2 = 5 m/s
Final velocity of ball A V1 = 6 m/s
Find:
Final velocity of ball B V2
Computation:
Using conservation of momentum;
M1U1 + M2U2 = M1V1 + M2V2
(12)(15) + (36)(5) = (12)(6) + (36)(v2)
180 + 180 = 72 + (36)(v2)
Final velocity of ball B V2 = 8 m/s