Answer:
50.2°
Step-by-step explanation:
[tex]\cos \angle D = 0.64\\\\\angle D = \cos^{-1}(0.64)\\\\\angle D = 50.20818\\\\\angle D \approx 50.2\degree[/tex]
The measurement of ∠D to the nearest tenth of a degree will be 50.2°. The obtained angle is an acute angle.
An acute triangle is a triangle formed by any angles that are less than 90 degrees. The angles should be less than 90 for the acute angle.
The given relation in the problem is;
[tex]\rm cos \angle D=0.64[/tex]
The calculation to find the acute angle is;
[tex]\rm cos \angle D = 0.64 \\\\ \angle D =cos^{-1}(0.64) \\\\ \angle D=50.20818 \\\\ \angle D =50.2 ^0[/tex]
Hence the measure of ∠D to the nearest tenth of a degree will be 50.2°.
To learn more about the acute angle refer to the link;
https://brainly.com/question/10334248?referrer=searchResults
