Answer:
[tex]x=\frac{-9}{7}[/tex]
[tex]y=\frac{-17}{7}[/tex]
Step-by-step explanation:
We have been given the equation:
[tex]3x-2y-1=0[/tex]
And [tex]y=5x+4[/tex]
Second equation can be rewritten as:
[tex]5x-y=-4[/tex]
We will solve the equations:
[tex]3x-2y=1[/tex] (1)
[tex]5x-y=-4[/tex] (2)
Multiply equation (1) by 5 and equation (2) by 3 we get:
[tex]15x-10y=5[/tex] (3)
[tex]15x-3y=-12[/tex] (4)
Now, subtract (4) from (3) we get:
[tex]-7y=17[/tex]
[tex]y=\frac{-17}{7}[/tex]
Now substitute [tex]y=\frac{-17}{7}[/tex] in equation (1) we get:
[tex]3x-2{\frac{-17}{7}}=1[/tex]
[tex]3x+\frac{34}{7}=1[/tex]
[tex]21x=-27[/tex]
[tex]x=\frac[-27}{21}[/tex]
[tex]x=\frac{-9}{7}[/tex]
