What is the probability, that a leap year selected at random will contain 53 Sundays?
Sol.: A leap year has 366 days, therefore 52 weeks i.e. 52 Sunday and 2 days.
The remaining 2 days may be any of the following :
(i) Sunday and Monday
(ii) Monday and Tuesday
(iii) Tuesday and Wednesday
(iv) Wednesday and Thursday
(v) Thursday and Friday
(vi) Friday and Saturday
(vii) Saturday and Sunday
For having 53 Sundays in a year, one of the remaining 2 days must be a Sunday.
n(S) = 7
n(E) = 2
P(E) = n(E) / n(S) = 2 / 7
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