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If you are asking for the line which passes through (-2,5) and is perpendicular to y=1/2(x) + 5 then the method is as follows. 

1) Note that the gradient of y = 1/2(x) + 5 is 1/2. It is the number before the x. 

2) Two perpendicular lines have gradients which multiply to give -1, so let 1/2m = -1. Then m = -2 

3) Substitute into the following equation: 
y - b = m(x - a), for a line with gradient m, passing through (a,b). 

y - (5) = -2(x - (-2)) 

y - 5 = -2x - 4 

y = -2x + 1

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