Respuesta :

vector QP= (-5+6, 11-4) = (1, 7)
its magnitude is QP= sqrt( 1 + 49)= sqrt (50)=5sqrt2

Answer and Step-by-step explanation:

We see that the vector is written a QP.

Usually, when finding the vector in component form, it is in this form.

PQ = < q1 - p1,q2 - p2> = <v1,v2> = v

In this situation, Q and P are switched.

QP = < p1 - q1, p2 - q2> = <v1,v2> = v

Now, we plug in our values.

QP = < -5 - -6, 11 - 4 > = < 1 , 7 >

The component form of our vector is <1, 7>

To find the magnitude, we do this:

[tex]||v|| = \sqrt{(p1 - q1)^2 + ( p2 - q2)^2} = \sqrt{(v1)^2+ (v2)^2}[/tex]

We already got the first part of this formula, so we plug in our vector into the second portion of the formula.

[tex]||v|| = \sqrt{(1)^2 + (7)^2} \\\\\\||v|| = \sqrt{1 + 49} \\\\\\||v|| = \sqrt{50} \\\\\\[/tex]

This simplifies down to [tex]2\sqrt{5}[/tex], but the answer choice we are given shows [tex]\sqrt{50}[/tex]

The magnitude of vector QP is [tex]\sqrt{50}[/tex].

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