Respuesta :
arithmetic sequence general term is an+1 - an =an - an-1= ... = a2 -a1=c
but we have an = 2 + (n - 1)(6) as an expression of the sequence, so c=6
and then an - an -1 =c = 6, from where an = an-1 + 6
but we have an = 2 + (n - 1)(6) as an expression of the sequence, so c=6
and then an - an -1 =c = 6, from where an = an-1 + 6
Answer:
The nth term for the arithmetic sequence is given by:
[tex]a_n = a_1+(n-1)d[/tex]
where,
[tex]a_1[/tex] is the first term
n is the number of terms and
d is the common difference for two consecutive terms.
As per the statement:
A certain arithmetic sequence has the following explicit formula for the nth term:
[tex]a_n = 2+(n-1)(6)[/tex]
⇒[tex]a_1 = 2[/tex] and d = 6
The recursive formula for the arithmetic sequence is given by:
[tex]a_n = a_{n-1}+d[/tex]
Substitute the given values we have;
[tex]a_n = a_{n-1}+6[/tex]
⇒the following recursive formula is, [tex]a_n = a_{n-1}+6[/tex]
Therefore, the number belongs in the blank space in the recursive formula is, 6