Respuesta :
The energy (E) per photon is expressed by Planck's equation: E = hf, where f is
the frequency and h is Planck's constant, experimentally determined to be
6.625 * 10**-34 joule-seconds. So to find E, we multiply h by the frequency
and obtain E = hf = (6.625 * 10**-34)(7.0 * 10**14) = 46.375 * 10**-20 joule
or in standard notation, E = 4.6375 * 10**-19 joule per photon.
Hope this answers your question.Sorry if I calculated wrong.
the frequency and h is Planck's constant, experimentally determined to be
6.625 * 10**-34 joule-seconds. So to find E, we multiply h by the frequency
and obtain E = hf = (6.625 * 10**-34)(7.0 * 10**14) = 46.375 * 10**-20 joule
or in standard notation, E = 4.6375 * 10**-19 joule per photon.
Hope this answers your question.Sorry if I calculated wrong.
Answer : The energy of one photon is [tex]4.65\times 10^{-19}J[/tex]
Explanation : Given,
Frequency of blue light = [tex]7.02\times 10^{14}Hz=7.02\times 10^{14}s^{-1}[/tex]
Formula used :
[tex]E=h\nu[/tex]
where,
[tex]\nu[/tex] = frequency of blue light
h = Planck's constant = [tex]6.626\times 10^{-34}Js[/tex]
E = energy of one photon = ?
Now put all the given values in the above formula, we get:
[tex]E=(6.626\times 10^{-34}Js)\times (7.02\times 10^{14}s^{-1})[/tex]
[tex]E=4.65\times 10^{-19}J[/tex]
Therefore, the energy of one photon is [tex]4.65\times 10^{-19}J[/tex]