Respuesta :

emma020

Answer:

5.  Since ∠CBD ≅ ∠CDB and ∠BAE ≅ ∠DEA, ΔABD and ΔBDE are equal. Therefore, the distances AD and EB are the same.

6.  Since ∠EBC ≅ ∠ECB and AE ≅ DE, ΔABE and ΔCDE are equal. Therefore, the distances AB and DC are the same.

I hope this helps!

mhanifa

Answer:

Question 5

ΔCBD is isosceles as angles B and D are congruent

ΔCAE is also isosceles as angles A and E are congruent

CA ≅ CE as the triangle ΔCAE is isosceles

  • AB = AC - BC, ED = EC - DC ⇒ AB ≅ ED
  • ∠BAE ≅ ∠DEA - given
  • AE ≅ EA - reflexive property
  • ΔBAE ≅ ΔDEA - SAS congruency theorem

AD ≅ EB - corresponding parts of congruent triangles

Question 6

  • ∠EBC ≅ ECB ⇒ ΔECB is isosceles ⇒ EB ≅ EC
  • AE ≅ DE - given
  • ∠AEB ≅ ∠DEC - vertical angles

ΔAEB ≅ ΔDEC - SAS congruency theorem

AB ≅ DC - corresponding parts of congruent triangles

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