Answer:
Slope: [tex]-\frac{1}{3}[/tex]
y-intercept: (0, 5)
Linear function: y = [tex]-\frac{1}{3}x + 5[/tex]
Step-by-step explanation:
To find the slope, use this formula: [tex]\frac{y2-y1}{x2-x1}[/tex] (you need 2 points)
I'll use (0, 5) and (3, 4):
[tex]\frac{4-5}{3-0} = -\frac{1}{3}[/tex]
Recall that the y-intercept is the point that lies on the y-axis of the function (in that point, the x-coordinate is 0). When looking at the graph, the only point at which the line intersects the y-axis is (0, 5), so that is your y-intercept. At that point, the x-coordinate is 0.
I'm not sure if the question wants you to put the equation for the linear function in slope-intercept form, but I'm assuming it does since it asked you for the slope and y-intercept. So, to find the equation in slope-intercept form, first recall that slope-intercept form is y = mx + b, where m is the slope and b is your y-intercept. At that point, just plug in your values to get y = [tex]-\frac{1}{3}x + 5[/tex]
