If LM = 6, what is the perimeter of △PKQ?
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Answer:
KM=LN Given
KM=KL+LM Segment Addition Postulate
LN=LM+MN Segment Addition Postulate
KL+LM=LM+MN Substitution Property of Equality
KL=MN Subtraction Property of Equality this is the formula :)
Step-by-step explanation:
Answer:
42
Step-by-step explanation:
3/(3+x-6)=5/(5+x)
cross multiply
3(5+x)=5(3+x-6)
15+3x=15+5x-30
15+3x=5x-15
15+15=5x-3x
30=2x
x=15
That means KQ=15 and PK=15-6=9. Now we have to find PQ, which is the same as JM. We’ll call that length b.
5/15=6/b
cross multiply
5b=90
b=18
15+9+18=42