Answer:
the thermal energy transferred is 183,226.68 J
Explanation:
Given;
mass of iron skillet, m = 5.1 kg
initial temperature, t₁ = 295 K
final temperature, t₂ = 373 K
The thermal energy transferred is calculated as;
Q = mcΔt
where;
Δt is change in temperature, = t₂ - t₁
c is specific heat capacity of iron = 460.6 J/kg.K
Q = 5.1 x 460.6 x (373 - 295)
Q = 183,226.68 J
Therefore, the thermal energy transferred is 183,226.68 J
