Answer:
7,540.64 m^2
Step-by-step explanation:
The area enclosed by the track may be computed as the sum of the area of the 2 semicircles and a rectangle.
The area of a semicircle is given as
A = 1/2 Pi r^2 where r is the radius of the semicircle. Since there are 2 semicircles, the area of the two will be
= Pi r^2
r = 52/2 = 26 m
Hence the area of the two semicircles
=3.14 * 26^2
= 2,122.64 m^2
The area of the rectangle is the product of its length and width
= 104 * 52
= 5408 m^2
Total area covered by the track
= 2,122.64 + 5,408
= 7,540.64 m^2
