Answer:
Ba(NO₃)₂(s) ⇒ BaO(s) + N₂(g) + 3 O₂(g)
Explanation:
Let's consider the unbalanced equation for the decomposition reaction of solid barium nitrate.
Ba(NO₃)₂(s) ⇒ BaO(s) + N₂(g) + O₂(g)
We can see that Ba atoms and N atoms are balanced, but we have 6 O atoms to the left side and 2 O atoms to the right. We can get the balanced equation by multiplying O₂(g) by 3.
Ba(NO₃)₂(s) ⇒ BaO(s) + N₂(g) + 3 O₂(g)