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The driver of a 1.5 x 10^3 kg car is traveling cast at 10 ms and increases its speed to 30 m/s east over 15 seconds. What is the initial and final momentum of the body? What is the net force acting on it?

Respuesta :

abidemiokin

Answer:

See explanations below

Explanation:

Force = m(v-u)/t

mass m = 1.5*10^3kg = 1500kg

v = 30m/s

u = 10m/s

Time t = 15secs

F = 1500(30-10)/15

F = 1500(20)/15

F = 100 * 20

F = 2000N

Force acting on it is 2000N

momentum = mass * velocity

final momentum = 1500 * 30

final momentum = 45000kgm/s

initial momentum = 1500 * 10

initial momentum = 15000kgm/s

asuwafohjames

The initial momentum, Final momentum and net force acting on the body are 15000 kgm/s, 45000 kgm/s,  and 2000 N respectively.

To solve for initial momentum, Final momentum, and average force, we use the formulas below.

⇒ Formulas

  • M = mu................. Equation 1
  • M' = mv................... Equation 2
  • F = M'-M/t................ Equation 3

⇒ Where:

  • M = Initial momentum of the car
  • M' = Final momentum of the car
  • u = Initial velocity'
  • v = Final velocity
  • t = time
  • F = net force acting on the car.

From the question,

⇒ For The Initial momentum

  • m = 1.5×10³ kg
  • u = 10 m/s east

⇒ Substitute these values into equation 1

  • M = 1.5×10³×10
  • M = 15000 kgm/s

Also for Final momentum,

⇒ Given:

  • v = 30 m/s

⇒ Substitute into equation 2

  • M' = 1.5×10³×30
  • M' = 45000 kgm/s

And finally for net force,

⇒ Given:

  • t = 15 seconds

⇒ substitute into equation 3

  • F = (45000-15000)/15
  • F = 30000/15
  • F = 2000 N

Hence,The initial momentum, Final momentum and net force acting on the body are 15000 kgm/s, 45000 kgm/s and 2000 N respectively.

Learn more about momentum mere: https://brainly.com/question/1591712

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