In this triangle cosA/CosB= ?
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Answer:
Step-by-step explanation:
[tex]\frac{cos A}{cos B} =\frac{\frac{AC}{AB} }{\frac{BC}{AB} } =\frac{AC}{AB} \times \frac{AB}{BC} =\frac{AC}{BC} =\frac{3}{3} =1[/tex]
The value of cosA divided by cosB is equal to 1.
Trigonometric Identities are equality statements that hold true for all values of the variables in the equation and that use trigonometry functions. There are numerous distinctive trigonometric identities that relate to a triangle's side length and angle.
It is given that in the right-angle triangle ABC the three sides are AB = 4.24, BC = 3 and AC = 3.
The value of cosine is the ratio of the base of the right-angle triangle and the hypotenuse of the right-angle triangle.
The value of cosA is calculated as below:-
cosA = 4.24 / 3
The value of cosB is calculated as below:-
cosB = 4.24 / 3
Calculating the ratio of cosA and cosB.
cosA / cosB = [ 4.24 / 3 ] ÷ [ 4.24 / 3 ]
cosA / cosB = 1
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