Respuesta :
Answer:
the change in speed of the sled after 3.0 s is 60 m/s.
Explanation:
Given;
constant acceleration of the sled, a = 20 m/s²
change in time of motion, dt = 3.0 s
The change in speed of the sled after 3.0 s is calculated as;
[tex]a = \frac{dv}{dt} \\\\dv = a \times dt\\\\dv = 20 \ \times \ 3\\\\dv = 60 \ m/s[/tex]
Therefore, the change in speed of the sled after 3.0 s is 60 m/s.
The speed of the sled change in 3.00 seconds is 60m/s.
Given that,
- The constant acceleration of magnitude [tex]20 m/s^2[/tex].
- And, the time taken is 3.00 seconds.
Based on the above information, the calculation is as follows:
[tex]= 20 \times 3[/tex]
= 60 m/s
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