Answer:
0.11507
Step-by-step explanation:
A normal distribution has a mean of µ = 70 with σ = 10. If one score is randomly selected from this distribution, what is the probability that the score will be greater than X = 82?
We solve this question using z score formula:
z = (x-μ)/σ,
where
x is the raw score = 82
μ is the population mean = 70
σ is the population standard deviation = 10
z = 82 - 70/10
z = 1.2
Probability value from Z-Table:
P(x<82) = 0.88493
P(x>82) = 1 - P(x<82) = 0.11507
Therefore, the probability that the score will be greater than X = 82 is
0.11507
