Answer:
2 liters of HBr is needed to completely react with the 50 g of salt.
Explanation:
First of all, we determine the reaction:
2HBr + CaCO₃ → CaBr₂ + CO₂ + H₂O
We need to calculate, moles of carbonate in order to state the stoichiometry (1:2)
50 g . 1mol / 100.08g = 0.499 mol
1 mol of salt need 2 moles of acid to react, according to stoichiometry
Then, 0.499 moles of salt, will react with (0.499 . 2)/1 = 0.999 moles
As we have the [HBr], we can calculate the volume.
M = mol/L → we replace → 0.50 mol/L = 0.999 mol /L
L = 0.999 mol/0.50 mol → 1.99 L ≅ 2L
