Answer:
A= [tex]4x+8[/tex]
B= [tex]8x+6x \\or\\ 16x[/tex]
C= [tex]8x+12[/tex]
D= [tex]6x+6y+6z[/tex]
Step-by-step explanation:
Distributing, or the means to divide something/create a share or part of something is when we multiply the sum of two or more addends by a number to achieve the same result as multiplying each addend individually by the number then adding the products together.
With this said, part A would look like this:
[tex]4(x+2)\\4(x) + 4(2) = ?\\4x + 8[/tex]
Now, the problem doesn't specifically state to solve the problem, but if you wanted too it would look like this:
[tex]4x + 8=0\\-8 \\4x=-8\\divide 4\\4=GCF\\x=-2[/tex]
Since we are just looking for the equation, the following problems would appear as so:
B:
[tex](6+8)*x\\x(8) + x(6)\\8x+6x\\14x[/tex]
C:
[tex]4(2x+3)\\4(2x)+4(3)\\8x+12[/tex]
D:
[tex]6(x+y+z)\\6(x) +6(y)+6(z)\\6x+6y+6z[/tex]
Another way to view the distributive property is that your distributing the number outside the parenthesis to all the number inside as such.
I would be happy to help you again in the future and hope that this provided you with some clarification! Have a nice day! :D
