Respuesta :
Answer:
the probability that A is the overall winner is 5/14 or 0.35714
Step-by-step explanation:
Given the data in the question;
probability that A is the overall winner P[A is the overall winner]
⇒ [tex]P_{A}[/tex][tex]P_{A}[/tex] + [tex]P_{A}[/tex][tex]P_{C}[/tex][tex]P_{B}[/tex][tex]P_{A}[/tex][tex]P_{A}[/tex] + [tex]P_{A}[/tex][tex]P_{C}[/tex][tex]P_{B}[/tex][tex]P_{A}[/tex][tex]P_{C}[/tex][tex]P_{B}[/tex][tex]P_{A}[/tex] [tex]P_{A}[/tex] + ................
= [tex]P_{B}[/tex][tex]P_{C}[/tex][tex]P_{A}[/tex][tex]P_{A}[/tex] + [tex]P_{B}[/tex][tex]P_{C}[/tex][tex]P_{A}[/tex][tex]P_{B}[/tex][tex]P_{C}[/tex][tex]P_{A}[/tex][tex]P_{A}[/tex] + [tex]P_{B}[/tex][tex]P_{C}[/tex][tex]P_{A}[/tex][tex]P_{B}[/tex][tex]P_{C}[/tex][tex]P_{B}[/tex][tex]P_{C}[/tex][tex]P_{A}[/tex] + ........
P(A) = [tex]\frac{1}{2}[/tex] = [tex]P_{B}[/tex] = [tex]P_{C}[/tex] ∴{ they are evenly matched player}
so P(A is overall winner) will be;
= ([tex]\frac{1}{2}[/tex])² + ([tex]\frac{1}{2}[/tex])⁵ + ([tex]\frac{1}{2}[/tex])⁸ + ..........+ ([tex]\frac{1}{2}[/tex])⁴ + ([tex]\frac{1}{2}[/tex])⁷ + ([tex]\frac{1}{2}[/tex])¹⁰ + .............
= ([tex]\frac{1}{2}[/tex])² [1 + ([tex]\frac{1}{2}[/tex])³ + ([tex]\frac{1}{2}[/tex])⁶ + .........] + ([tex]\frac{1}{2}[/tex])⁴[1 + ([tex]\frac{1}{2}[/tex])³ + ([tex]\frac{1}{2}[/tex])⁶ + .........]
= [ ([tex]\frac{1}{2}[/tex])² + ([tex]\frac{1}{2}[/tex])⁴ ] [ 1 / 1 - ([tex]\frac{1}{2}[/tex])³ ]
= [ ([tex]\frac{1}{4}[/tex]) + ([tex]\frac{1}{16}[/tex]) ] [ [tex]\frac{8}{7}[/tex] ]
= [tex]\frac{5}{16}[/tex] × [tex]\frac{8}{7}[/tex]
= 5/14 or 0.35714
Therefore, the probability that A is the overall winner is 5/14 or 0.35714
The probability that A is the overall winner is; 5/14
- Let P be the chance that a player will win the tournament when he gets a new opportunity to play against the victor of the previous game.
Now, if the player loses, then it means that two games in a row are won by the same player, and then the tournament will be over. Thus; [tex]P_{L}[/tex] = 0
- However, If the player wins first, and then loses his next game, it means that such a player will have to hope for a new opportunity. What this implies is that the player to whom he lost to will not win the next game. The probability of this happening is; [tex]P_{WLX}[/tex] = ¹/₂ × ¹/₂ × ¹/₂;
[tex]P_{WLX}[/tex] = ¹/₈
Furthermore from that above, he will have another chance to win twice in a row which gives a probability in form of a geometric series as;
¹/₄ + (¹/₄ × ¹/₈ ) + (¹/₄ × ¹/₈² ) + (¹/₄ × ¹/₈³ ) + ........
Now, for that series, as n approaches infinity, the sum of the series would give us;
∑ = ¹/₄(1/(1 - ¹/₈ ))
⇒ ¹/₄(⁸/₇)
⇒ ²/₇
Since player C's first game would already be against another game's winner, then it means that P is also the chance player C will win the tournament but the probability that player A will win is same as probability that player B will win which is;
[1 - (²/₇)]/2
⇒ ⁵/₇ × ¹/₂
P(A) = P(B) = ⁵/₁₄
Read more on probability at; https://brainly.com/question/24855677
