Answer:
a.1633rad/min
b.1715feet/min
Step-by-step explanation:
We are given that
Diameter of wheel, d=2.1 feet
Radius of wheel, r=[tex]\frac{d}{2}=\frac{2.1}{2}[/tex]feet
Rate=260 rev/min
a. We have to find the angular speed of the wheel in rad/min
1 rev=[tex]2\pi[/tex]radian
Where [tex]\pi=3.14[/tex]
Using the value
Angular speed=[tex]260\times 2\times 3.14/min[/tex]
Angular speed,[tex]\omega=1633rad/min[/tex]
(b)
Speed=[tex]r\omega[/tex]
Using the formula
Speed of the cyclist=[tex]\frac{2.1}{2}\times 1633[/tex]feet/min
Speed of the cyclist=1714.65[tex]\approx 1715[/tex]feet/min
