Answer:
x=1 and y= 5[tex]\frac{1}{4}[/tex]
Step-by-step explanation:
To solve this, lets take the first equation and find the x value.
Because it is ordered in standard form, we need to convert to slope-intercept form, and isolate the y.
5x+4y=16
-5x -5x
4y=-5x+16
÷4 ÷4 ÷4
y=[tex]\frac{-5}{4}[/tex]+4
or
y=-1[tex]\frac{1}{4}[/tex]+4
or
y= 5[tex]\frac{1}{4}[/tex]
Now that we have the y value, we can use this to find the x value by inserting it into either equation, since they both have y values in them. Going with the first one again, lets try it:
5x+4([tex]\frac{-5}{4}[/tex]+4)=16
5x-5+16=16
5x+11=16
-11 -11
5x=5
÷5 ÷5
x=1 and y= 5[tex]\frac{1}{4}[/tex]
