Answer:
Explanation:
From the information given:
The schematic diagram for the system and the force body diagrams for each charge can be seen in the image attached below
(c)
The symbolic expressions for the net force on each object is as follows:
[tex]N_A = m_Ag \\ \\ F_{net}, A= F_A = \dfrac{kQ_AQ_B}{r^2}[/tex]
[tex]N_B = m_Bg \\ \\ F_{net}, B= F_B = \dfrac{kQ_AQ_B}{r^2}[/tex]
(d) From above
[tex]F_A =F_B[/tex]
[tex]m_Aa_A = m_Ba_B \\ \\ (6m_B)a_A = m_B a_B[/tex]
[tex]a_B = 6a_A[/tex]