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You push a box across the floor at a constant speed of 1 m/s, applying a horizontal constant force of magnitude 20 N. Your friend pushes the same box across the same floor at a constant speed of 2 m/s, applying a horizontal force. What is the magnitude of the force that your friend applies to the box

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onyebuchinnaji

Answer:

the force your friend applied on the box is 40 N.

Explanation:

Given;

speed of the box, v₁ = 1 m/s

force applied to the box, F₁ = 20 N

the speed of the box when your friend pushes it, v₂ = 2 m/s

then your friends applied force, F₂ = ?

Assuming the time, t, through which both forces were applied and mass of the box, m, to be constant;

[tex]F_1 = \frac{mv_1}{t} \\\\\frac{m}{t} = \frac{F_1}{v_1} = \frac{F_2}{v_2}[/tex]

[tex]F_2 = \frac{F_1v_2}{v_1} \\\\F_2 = \frac{20\times 2}{1} \\\\F_2 = 40 \ N[/tex]

Therefore, the force your friend applied on the box is 40 N.

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