Respuesta :
Answer:
a) #_total = 4 10²³ photons / h, b) # _photon_area = 3 10²² photons
Explanation:
a) Let's start by calculating the energy of an emitted photon
E₀ = h f
c = λ f
substituting
E₀ = h c /λ
E₀ = [tex]\frac{6.62 \ 10^{-34} \ 3 \ 10^{8} }{550 \ 10^{9} }[/tex]
E₀ = 3.6 10⁻¹⁹ J
Let's use a direct proportion rule (res rule) if a photon has Eo, how many photons are there in 55W
#_foton = 55 / E₀
# _photon = 55 / 3.6 10⁻¹⁹ = 15.27 10¹⁹ photons
This version is with 100% if the conversion is 75%, how many footnes are there
#_foton_real = # _foton 75/100
#real_photon = 15.27 10¹⁹ 0.75
# _real_photon = 11.45 10¹⁹ photons
this is the broadcast in a second
#_total = # _real_photon t
#_total = 11.45 10¹⁹ 3600
#_total = 4.1 10²³ photons / h
#_total = 4 10²³ photons / h
b) This number of photons is constant, so after being emitted they are distributed on the surface of a sphere, in this case of radius r = 1.0 m
the volume of a sphere is
A = 4π r²
A = 4π 1²
A = 12,566 m²
the area of the plate is
A₁ = l₁ l₂
A₁ = 0.10 0.10
A₁ = 1 10⁻² m
Let's use a direct proportion rule, if there are 4.1 10²³ photons in an area A, how much are there in an area A₁
# _photon_area = #_total A₁ / A
# _photon_area = [tex]4.1 \ 10^{23} \ \frac{1 \ 10^{-2} }{12.566}[/tex]
# _photon_area = 3.26 10²²
as the number of photons must be a whole number
# _photon_area = 3 10²² photons
