Answer:2.51 s
Explanation:
Given
The radius of merry-go-round r=2 m
Speed of person at edge v=5 m/s
The person is in a uniform circular motion with constant velocity
time taken to complete one lap is
[tex]t=\frac{\text{distance}}{\text{speed}}=\frac{2\pi \cdot 2}{5}\\\\t=\frac{12.568}{5}=2.5136\ s[/tex]
