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Using the equation below, how many liters of water can be made from 7.6 L of oxygen gas at STP?

Using the equation below how many liters of water can be made from 76 L of oxygen gas at STP class=

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Answer:

V = 15.2 L

Explanation:

STP means that T = 273 K and P = 1 atm.

We use the PV=nRT equation to convert the given liters of oxygen to moles:

  • 1 atm * 7.6 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 273 K
  • n = 0.340 mol

Now we convert O₂ moles to H₂O moles, using the stoichiometric coefficients of the equation:

  • 0.340 mol O₂ * [tex]\frac{2molH_2O}{1molO_2}[/tex] = 0.68 mol H₂O

Finally we use the PV=nRT equation once again to convert 0.68 moles of H₂O to liters:

  • 1 atm * V = 0.68 * 0.082 atm·L·mol⁻¹·K⁻¹ * 273 K
  • V = 15.2 L

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