Answer:
[tex](f\circ g)(-5)=85[/tex]
Step-by-step explanation:
We are given:
[tex]\displaystyle f(x)=4x+5\text{ and } g(x)=x^2+x[/tex]
And we want to find:
[tex](f\circ g)(-5)[/tex]
This is equivalent to:
[tex]\displaystyle =f(g(-5))[/tex]
So, we will evaluate g(-5) first, which yields:
[tex]\displaystyle g(-5)=(-5)^2+(-5)=25-5=20[/tex]
So:
[tex]=f(g(-5))=f(20)[/tex]
Then:
[tex]\displaystyle f(20)=4(20)+5=80+5=85[/tex]
Therefore:
[tex](f\circ g)(-5)=85[/tex]
