milianijolie
contestada

A student increases the temperature of a 200 cm3 balloon from 60°C to 100 °C.
What will the new volume of the balloon be? Round your answer to one decimal
point.
(to convert Celsius to Kelvin, add 273.15)

Answer?

Respuesta :

Answer:

178.56 cm3

Explanation:

V1/T1=V2/T2

V2=V1T1/T2

V1 (volume) is 200 cm3

T1 (temperature) is 60°C but convert into Kelvin

T2 (temperature) is 100 °C but convert into Kelvin

Plug in the values...

V2= (200 cm3)(60+273.15)/ (100+273.15)

V2=178.56 cm3

Answer:

178.56 cm3

Explanation: