Answer: 11.25 moles of [tex]O_2[/tex] will be required to completely react with 2.25 moles of [tex]C_3H_8[/tex].
Explanation:
The balanced chemical equation is:
[tex]C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(g)[/tex]
According to stoichiometry :
1 mole of [tex]C_3H_8[/tex] require = 5 moles of [tex]O_2[/tex]
Thus 2.25 moles of [tex]C_3H_8[/tex] will require=[tex]\frac{5}{1}\times 2.25=11.25moles[/tex] of [tex]O_2[/tex]
Thus 11.25 moles of [tex]O_2[/tex] will be required to completely react with 2.25 moles of [tex]C_3H_8[/tex].
