Answer:
The reading on the ammeter is 0 ampere
Explanation:
When two or more voltage sources are arranged in series as shown in the diagram, the resultant voltage is given by the sum of the voltages by taking into consideration the direction of the polarities of the voltage sources which can be either series aiding voltage source configuration or series opposing voltage source configuration
In the series aiding voltage source configuration, the positive terminal of one voltage source is connected to the negative terminal of the next voltage source such that the current flows in the same direction in both sources of the voltage in the circuit and the resultant voltage source is given by adding the individual voltage sources together
However, in the series opposing voltage source configuration, the positive terminal of one voltage source is connected to the positive terminal of the next voltage source such that the current flows in opposite direction in both voltage sources and the voltage across the entire voltage sources is given by finding the sum of the differences of the opposing voltage sources
The arrangement of the voltage sources in the question is one of a series opposing voltage configuration and the voltage across both voltage sources is given by subtracting one (usually the smaller voltage source) from the other as follows;
[tex]V_{(series \ opposing)}[/tex] = V₁ - V₂
Where;
V₁ = The voltage of one (usually the larger) of the voltage source = 1.5 V
V₂ = The voltage of the other voltage source = 1.5 V
Therefore;
[tex]V_{(series \ opposing)}[/tex] = 1.5 V - 1.5 V = 0 V
The reading on the ammeter = The current in the circuit, 'I', which is given as follows;
V = I·R
∴ I = V/R = 0/R = 0
I = 0 A (ampere)
The reading on the ammeter = I = 0 A (Current cannot flow without the presence of a voltage).
